Please explain to me how to do this question!!!!!!!
A beam consists of singly ionised neon-20 atoms all travelling at the same speed, 3*10^5 m/s, through a vacuum. As the beam passes through the magnetic field it follows a circular path of radius 0.125m. The force on each of of mass 3.32*10^-26 kg is 2.4*10^-14 N.
Calculate the magnetic field strength or flux density in teslas.
Thank you!
As a charged particle passes through a magnetic field it experiences a force perpendicular to its direction of motion.
That is a centripetal force leading to centripetal acceleration v^2/r
so
F = q v B
and
F = m v^2/r
so
q v B = m v^2 / r
and finally
r = m v/(q B)
To calculate the magnetic field strength or flux density in teslas, you can use the formula for the force on a charged particle moving through a magnetic field:
F = qvB
where F is the force, q is the charge of the particle, v is its velocity, and B is the magnetic field strength.
In this case, we can assume that each atom of neon-20 is singly ionized, which means it has a charge q of +e, where e is the elementary charge (1.60 * 10^-19 C). The velocity v is given as 3.00 * 10^5 m/s.
We are also given the force F, which is 2.40 * 10^-14 N.
Rearranging the formula, we have:
B = F / (qv)
Now we can substitute the values into the formula:
B = (2.40 * 10^-14 N) / ((1.60 * 10^-19 C) * (3.00 * 10^5 m/s))
Calculating this expression gives us the value of B in teslas.