The density of solution of sulfuric acid is 1.29 g/cm3, and it is 38.1% acid by mass. What is the mass, in grams, of 25.0 mL of sulfuric acid?
1.29 g/cc x 25 cc x 0.381
25g
To find the mass of 25.0 mL of sulfuric acid, we need to consider both the density and the percentage of acid by mass.
Step 1: Calculate the volume in cm³.
The given volume is 25.0 mL, which is equivalent to 25.0 cm³.
Step 2: Calculate the mass of the solution.
The density of the solution is 1.29 g/cm³.
Mass = Density x Volume
Mass = 1.29 g/cm³ x 25.0 cm³
Step 3: Calculate the mass of the acid.
The solution is 38.1% acid by mass.
Mass of acid = 38.1% x Mass of solution
Now we can calculate the mass of 25.0 mL of sulfuric acid.
Mass = 1.29 g/cm³ x 25.0 cm³ = 32.25 g
Mass of acid = 38.1% x 32.25 g = 12.29 g
Therefore, the mass of 25.0 mL of sulfuric acid is 12.29 grams.
To find the mass of 25.0 mL of sulfuric acid, we need to use the density and the percentage of acid in the solution.
First, let's convert the volume from milliliters to cubic centimeters (cm^3), since the density is given in g/cm^3.
Given:
Density of sulfuric acid solution = 1.29 g/cm^3
Percentage of acid by mass = 38.1%
Volume of sulfuric acid = 25.0 mL
1 mL is equivalent to 1 cm^3. Therefore, the volume of sulfuric acid is 25.0 cm^3.
Next, we can use the formula: mass = density x volume
mass = 1.29 g/cm^3 x 25.0 cm^3
mass = 32.25 g
Therefore, the mass of 25.0 mL of sulfuric acid is 32.25 grams.