am i correct?


1(2x)^3 + 3(2x)^2*(-5y)^1 + 3(2x)^1*(-5y)^2 + 1(-5y)^3

answer

(2x-5y)^3

Anything times 1 or to the first power is itself. Unless you have typos, here is what I get:

(2x)^3 + 12x^2 * (-5y) + 6x * 25y^2 - 125y^3 =

8x^3 - 60x^2y + 150xy^2 - 125y^3

luckily, the answers agree!

Ok,thank you guys! :)

To determine if your answer is correct, we can simplify the expression using the binomial expansion formula:

(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

Let's apply this formula to the given expression step by step:

1(2x)^3 + 3(2x)^2*(-5y)^1 + 3(2x)^1*(-5y)^2 + 1(-5y)^3

= (8x^3) + 3(4x^2)(-5y) + 3(2x)(25y^2) + (-125y^3)

= 8x^3 - 60x^2y + 150xy^2 - 125y^3

Now, let's compare this simplified expression with your answer, (2x - 5y)^3.

(2x - 5y)^3 = (2x - 5y)(2x - 5y)(2x - 5y)
Expanding this using the distributive property gives us:

= (4x^2 - 20xy + 25y^2)(2x - 5y)
= 8x^3 - 40x^2y + 50xy^2 - 20x^2y + 100xy^2 - 125y^3
= 8x^3 - 60x^2y + 150xy^2 - 125y^3

As we can see, your answer (2x - 5y)^3 matches the simplified form of the given expression. Therefore, your answer is correct.