Use u-substitute to compute the following:

A) ∫((x)/((x^2)+5)) dx

B) ∫((sin(ln(x)))/(x)) dx

u = x^2+5

du = 2x dx
So, your integral is now
1/2 ∫ du/u

u= lnx
du = 1/x dx
∫sin(u) du