Things around you are emitting infrared radiation that includes the wavelength 1.44 10-5 m. What is the energy of the photons?
Ah, infrared radiation, huh? Well, let me bring my clown glasses and do some calculations for you. Hold on tight!
To find the energy of the photons, we can use Planck's equation: E = hν, where E is the energy, h is Planck's constant (6.626 x 10^-34 J·s), and ν (nu) is the frequency.
Now, to find the frequency, we can use the equation: c = λν, where c is the speed of light, and λ (lambda) is the wavelength. Rearranging, we get ν = c / λ.
The speed of light is approximately 3.00 x 10^8 m/s, and the given wavelength is 1.44 x 10^-5 m. Let's plug those values in:
ν = (3.00 x 10^8 m/s) / (1.44 x 10^-5 m) = 2.08 x 10^13 Hz
Now, we can find the energy:
E = (6.626 x 10^-34 J·s) * (2.08 x 10^13 Hz) = 1.38 x 10^-20 J
So, the energy of the photons emitting infrared radiation with a wavelength of 1.44 x 10^-5 m is approximately 1.38 x 10^-20 Joules. That's one energetic, yet invisible, party!
To calculate the energy of a photon with a given wavelength, you can use the equation:
E = hc / λ
Where:
E is the energy of the photon
h is Planck's constant (approximately 6.626 x 10^-34 J·s)
c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s)
λ is the wavelength of the radiation
Let's substitute the values into the equation:
E = (6.626 x 10^-34 J·s) * (3.00 x 10^8 m/s) / (1.44 x 10^-5 m)
Simplifying the calculation:
E = 1.454 x 10^-19 J
Therefore, the energy of the photons emitted with a wavelength of 1.44 x 10^-5 m is approximately 1.454 x 10^-19 J.
To determine the energy of photons with a given wavelength, you can use the equation:
E = hc/λ
Where:
E = Energy of photons
h = Planck's constant (6.626 x 10^-34 J·s)
c = Speed of light (3.00 x 10^8 m/s)
λ = Wavelength
In this case, the given wavelength is 1.44 x 10^-5 m. Plugging the values into the equation, we can find the energy of the photons:
E = (6.626 x 10^-34 J·s) x (3.00 x 10^8 m/s) / (1.44 x 10^-5 m)
Calculating this equation will give you the energy of the photons in joules (J).
Things could not get easier than this. I'm sure you are familiar with this equation:
E = hc/λ
Therefore, plug in the numbers and solve for energy.
E = (6.63 x 10^-34 J*s)(3.0 x 10^8 m/s) / (1.44 x 10^-5 m)
E = 1.38 x 10^-20 J