1. If a bat emits 10 sounds in 5 seconds, what is the frequency of the bat's vocal outbursts (rounded to first decimal place)

My answer: 2.0 Hz

2.If one crest has a 3 cm amplitude and interacts with another pulse to produce a crest 8 cm high this demonstration"
a) constructive interference
b) destructive interference
c) doppler effect
d) a node

my answer: a

3. A standing wave is set up in a pool 24 m long which contains 6 loops. What is the wavelength?

my answer: 24m

4.Which of the following is not an example of wave motion?
a) The sound of a tuba
b) a vibrating slinky showing crests and troughs
c) a person dancing
d) a tsunami event occurring after the earthquake
e) an earthquake's energy travelling through the core of the planet

my answer: c

thanks a lot!

You are welcome.

1. To calculate the frequency, you can use the formula: frequency = number of cycles / time. In this case, the bat emits 10 sounds in 5 seconds, so the frequency would be 10/5 = 2 Hz.

2. In this demonstration, we are given that one crest has a 3 cm amplitude and it interacts with another pulse to produce a crest 8 cm high. This indicates that the two pulses are adding up or reinforcing each other, which is known as constructive interference. Therefore, the correct answer would be "a) constructive interference."

3. In a standing wave, the wavelength is equal to twice the distance between consecutive nodes (or loops). In this case, the pool is 24 m long and contains 6 loops, so the distance between consecutive nodes would be 24 m / 6 = 4 m. Therefore, the wavelength would be 2 * 4 m = 8 m.

4. Wave motion is characterized by the transfer of energy through the oscillation or vibration of matter. In this given list, options a, b, d, and e all involve wave motion. However, option c, "a person dancing," does not involve the transfer of energy through oscillation or vibration of matter and is not an example of wave motion. Therefore, the correct answer would be "c) a person dancing."

I agree on all but #3.

If by loop they mean antinode they occur 6 times including the ends. The distance from a node to an antinode is 1/4 lambda.
I see ten quarter wavelengths in the 24 feet
so 10( lambda/4) = 24
lambda = 2.4 *4 = 9.6 meters