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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Saturday, April 19, 2014 at 10:17am.

- Linear programming -
**Damon**, Saturday, April 19, 2014 at 11:56amx = days at Loc 1

y = days at Loc 2

then limits and intecepts

deluxe 10x+20y >/= 2000 (0,100)(200,0)

better 20x+50y >/= 4200 (0,84)(210,0)

standard 13x+6y >/= 1200 (0,200)(92.3,0)

graph those

and cost constraint c = 500 x + 800 y

Now test upper corners

try (0,200) all loc 2

c = 800(200) = 160,000

try (210,0) all loc 1

c = 500(210) = 105,000 better

Try also the intersection of the other lines to see if you get a lower cost solution

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