In triangle abc, angle abc= ×deg,bc=× and ab=(×+10) ;find the value of x
The question makes no sense to me.
Are you saying that the angle has the same numerical value as the side BC ?
Interesting mix of linear measurement and angle measurement.
Are you using degrees or radians ?
so you could use any 0 < x < 180
e.g. if x = 20
then angle ABC = 20° , BC = 20 units of length and AB = 30 units of length, which would define a unique triangle, since the angle is contained between the two given sides.
etc.
The question would become interesting if you gave the third side a value in terms of x.
e.g
let the third side be x+20
then , by the cosine law we would have
(x+20)^ = x^2 + (x+10)^2 - 2(x)(x+10)cos x°
which would be a very difficult equation to solve:
just messing around with my calculator,
when x = 73
LS = 93^2 = 8649
RS = 8675 , which is the closest for x to be a whole number
As an exercise, find the angle ABC
if BC = 72.89
AB = 82.89 and
AC = 92.89