The mean score for all individuals who took the Law School Admission Test (LSAT) in 2010 was 155 and the standard deviation was 7.

9. What is the z score for a person, who received an LSAT score of 167?
a. +1.71
b. +1.64
c. +1.74
d. -1.71
10.What is the raw score for a person with a z score of -0.86?
a. 164
b. 146
c. 149
d. 161

Z = (score-mean)/SD

Insert the known values and solve for the unknown.

Answer

To find the z-score, you need to use the formula:

z = (x - μ) / σ

Where:
- x is the raw score (LSAT score in this case)
- μ is the mean score
- σ is the standard deviation

For question 9:
x = 167
μ = 155
σ = 7

Substituting the values into the formula:
z = (167 - 155) / 7
z ≈ 1.714

Therefore, the z-score for a person who received an LSAT score of 167 is approximately +1.71.

The correct answer choice for question 9 is a. +1.71.

For question 10:
z = -0.86
μ = 155
σ = 7

Rearranging the formula to solve for x:
x = z * σ + μ
x = -0.86 * 7 + 155
x ≈ 149.98

Therefore, the raw score for a person with a z-score of -0.86 is approximately 149.

The correct answer choice for question 10 is c. 149.