posted by EMILY on .
Calculate the potential at 25∘C for a cell that has the following ion concentrations: [Ag+] = 1.0×10−2M , 3.2×10−2M .
Your post isn't very clear. Do you mean this is a concentration cell with one half cell of 1E-2M and the other 3.2E-2.
If so then Ecell = -(0.05916/1)log (dilute/concd)
Consider a galvanic cell that uses the reaction
What is Ag? What's the other number for?