1. Find the boiling point of a solution composed of 110g of HgCl2 (a non-ionizing solute) in 175g of water.
mols HgCl2 = grams/molar mass
Substitute and solve for mols.
molality = m = mols/Kg solvent
Substitute and solve for m
delta T = i*Kb*m
Your post says i = 1
Kb = 1.51
Substitute and solve for delta T, then add to 100 C to find the new boiling point.
2. Find the freezing point of a solution composed of 50g IBr in 120 g of water. Assume 100% ionization. KBr = k1+Br1-.
I assume you made a typo and IBr really is KBr.
mols KBr = grams/molar mass.
Solve for mols.
molality = m = mols/kg solvent
Solve for m
delta T = i*Kf*m
i for KBr = 2
Kf = 1.86
Solve for delta T and subtract from 0 C to find the new freezing point.
delta T = i*Kf*m
i = 1
3,5,5 look just like 1 and 2.
6 and 7 are done by working backward.
delta T = i*Kf or Kb *m
You're given delta T, solve for m.
Then m = mols/kg solvent.
Solve for mols
Then mols = grams/molar mass. You're given mols and grams; solve for molar mass.
i = 1 for both 6 and 7
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