Posted by **Tyler** on Tuesday, April 15, 2014 at 11:13pm.

John is driving at a constant speed of 20.0 m/s when he passes Jane, who is traveling in the same direction at 15.0 m/s at the moment that John passes her. If Jane is accelerating at 2.0 m/s2, how far will Jane drive before she catches up to John? How much time passes from when John passes Jane until Jane catches back up with John? (You can assume all motion is on flat, level ground.)

- Math/Physics -
**bobpursley**, Wednesday, April 16, 2014 at 12:20am
John distance=20*time

Jane distance=15*time+1/2 a time^2

set them equal, solve for time

then solve for either distance in that time.

- Math/Physics -
**Bro**, Wednesday, April 16, 2014 at 1:22am
Why the 1/2 in 1/2*a*time^2?

## Answer This Question

## Related Questions

- Physics - John is driving at a constant speed of 20.0 m/s when he passes Jane, ...
- Physics - Jane and John, with masses of 50 kg and 60 kg, respectively, stand on ...
- physics - Jane and John, with masses of 50kg and 68kg , respectively, stand on a...
- physics - Jane and John, with masses of 54kg and 63kg , respectively, stand on a...
- Business Statistics - John & Jane are married. The probability that John watches...
- physics - While John is traveling along an interstate highway, he notices a 166 ...
- Physics - While John is traveling along an interstatehighway, he notices a 166 ...
- physics - While John is traveling along an interstate highway, he notices a 166 ...
- physics - while john is traveling along an interstate highway he notices a 160-...
- Physics - while john is traveling along an interstate highway, he notices a 160-...

More Related Questions