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January 26, 2015

January 26, 2015

Posted by **Tyler** on Tuesday, April 15, 2014 at 11:13pm.

- Math/Physics -
**bobpursley**, Wednesday, April 16, 2014 at 12:20amJohn distance=20*time

Jane distance=15*time+1/2 a time^2

set them equal, solve for time

then solve for either distance in that time.

- Math/Physics -
**Bro**, Wednesday, April 16, 2014 at 1:22amWhy the 1/2 in 1/2*a*time^2?

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