Given that the density of the supplied vinegar solution in this experiment is

1.025 g/mL, calculate the % acetic acid found in the vinegar sample.

Density = 1.025 g/mL; therefore, 100 mL has a mass of 1.025g/mL x 100 mL = 102.5g. 100 mL H2O should weigh 100 g; therefore, there are 2.5 g vinegar in the sample and that is 2.5%. This assumes that the volumes of vinegar and H2O are additive.

To calculate the percentage of acetic acid in a vinegar sample, you would need additional information such as the molar mass of acetic acid or the mass of the vinegar sample. However, if you have the concentration of acetic acid in the vinegar solution, you can use that information to calculate the percentage.

To calculate the percentage of acetic acid, you would follow these steps:

1. Find the mass of acetic acid in the vinegar sample:
- Multiply the volume of the vinegar sample by its density to find the mass of the vinegar.
- Multiply the mass of the vinegar by the concentration of acetic acid (expressed as a decimal) to find the mass of acetic acid.

2. Calculate the percentage of acetic acid:
- Divide the mass of acetic acid by the mass of the vinegar and multiply by 100 to find the percentage.

For example, let's say you have a 100 mL vinegar sample with a density of 1.025 g/mL and a concentration of acetic acid of 0.5 M.

1. Find the mass of acetic acid:
- Mass of vinegar = Volume of vinegar x density = 100 mL x 1.025 g/mL = 102.5 g
- Mass of acetic acid = Mass of vinegar x concentration = 102.5 g x 0.5 mol/L = 51.25 g

2. Calculate the percentage of acetic acid:
- Percentage of acetic acid = (Mass of acetic acid / Mass of vinegar) x 100 = (51.25 g / 102.5 g) x 100 = 50%

Therefore, the percentage of acetic acid in the vinegar sample is 50%.