Jorge finds that his standardized z score on an IQ is 2.0. What percentage of people did he score higher than?
a. 98
b. 96
c. 68
d. 34
Use either your tables available to your or use
http://davidmlane.com/hyperstat/z_table.html
to get .9772 or .98 from your choices
To find the percentage of people Jorge scored higher than, we need to analyze the standard normal distribution (also known as the z-distribution).
First, let's understand what a z-score represents. A z-score is a measure of how many standard deviations an individual's score is from the mean of the distribution. In this case, Jorge's standardized z-score is 2.0.
Typically, about 68% of the values in a normal distribution fall within one standard deviation of the mean, about 95% fall within two standard deviations, and about 99.7% fall within three standard deviations.
Since Jorge's z-score is 2.0, it means his score is two standard deviations above the mean. This indicates that he scored higher than approximately 95% of people.
Therefore, the correct answer is b. 96%.