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January 24, 2015

January 24, 2015

Posted by **Griffin Bilskie** on Monday, April 14, 2014 at 11:41pm.

- calculus -
**Steve**, Tuesday, April 15, 2014 at 12:11amSo, the height is 40/x^2

c(x) = 2x^2*5 + 4x(40/x^2)*2

= 10x^2 + 320/x

set the derivative to zero, and you find minimum cost at x = 2∛2

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