I have to write a balanced equation for the decompostion of solid copper (ii) sulfate to form the gaseous sulfur trioxide and solid coper (ii) oxide.

I would appreciate it if you could tell me if I have written it correctly.

CuSO4 >>> SO3 + CuO

If I did not write this correctly could you explain what I did wrong and how should I correct this problem.

You have written it correctly.

The given equation you wrote is not balanced correctly. Let's go step by step to balance it correctly:

The decomposition of solid copper (II) sulfate can be represented by the formula:

CuSO4(s) → SO3(g) + CuO(s)

To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the copper (Cu) atoms:

We have one copper atom on the left side and one copper atom on the right side, so the copper atoms are already balanced.

Next, let's balance the sulfur (S) atoms:

We have one sulfur atom on the left side and one sulfur atom on the right side, so the sulfur atoms are already balanced.

Finally, let's balance the oxygen (O) atoms:

On the left side, we have four oxygen atoms in the CuSO4 compound, while on the right side, we have three oxygen atoms in SO3 and one oxygen atom in CuO.

To balance the oxygen atoms, we need to add one more oxygen atom on the right side:

CuSO4(s) → SO3(g) + CuO(s) + O2(g)

Now, the equation is balanced with respect to the number of atoms of each element.

Therefore, the correct balanced equation for the decomposition of solid copper (II) sulfate to form gaseous sulfur trioxide and solid copper (II) oxide is:

CuSO4(s) → SO3(g) + CuO(s) + O2(g)