y = −x^2 + 8
Axis of symmetry?
What is the x value of your vertex ?
0 is the value of x
so the vertex is (0,8)
and the axis of symmetry is x = 0 , or the y-axis
That's what I put and it was marked wrong..it is a two part questions I got (0,8) correct but the axis of symmetry wrong...hmmm thanks!!
I am 100% sure that I am correct
the axis of symmetry is x = 0
For any vertical parabola , (like yours), if the vertex is (p , q), the axis of symmetry is x = p
To find the axis of symmetry of a quadratic function in the form of y = ax^2 + bx + c, you can use the formula x = -b / (2a).
In your given equation y = -x^2 + 8, we can observe that the coefficient of x^2 (a) is -1 and the coefficient of x (b) is 0.
Substituting these values into the formula, we have x = -0 / (2 * -1) = 0 / -2 = 0.
Therefore, the axis of symmetry of the given quadratic function is x = 0.