posted by dddd47906 on .
What is the number of permutations for the words:
You can arrange it in any order. You can also arrange it into any order of the letters.
You could use the math from FACTORIAL.
I need an answer ASAP!!!
as you know by now, after all the problems you have posted, n things can be permuted in n! ways.
If there are m duplicates, divide by m!
so, for PROPOSITION, since there are
there are 11!/(2!3!2!) distinguishable permutations of the letters.
Do the others in the same way.