2NBr3+63NaOH--->N2+3NaBr+3hobr
That doesn't look like the Jacksonville I know.
The given chemical equation is:
2NBr3 + 6NaOH ---> N2 + 3NaBr + 3H2O
Let's break down the equation and understand the reaction that is taking place.
Starting with the reactants:
- We have 2 molecules of NBr3 (nitrogen tribromide). This is a covalent compound formed by combining nitrogen (N) and bromine (Br).
- We have 6 molecules of NaOH (sodium hydroxide). This is an ionic compound formed by combining sodium (Na) and hydroxide (OH) ions.
The products formed are:
- We have 1 molecule of N2 (nitrogen gas). This is a diatomic molecule formed by two nitrogen atoms bonded together. It is a stable and inert gas.
- We have 3 molecules of NaBr (sodium bromide). This is an ionic compound formed by combining sodium (Na) and bromide (Br) ions.
- We have 3 molecules of H2O (water). This is a covalent compound formed by combining two hydrogen (H) atoms and one oxygen (O) atom.
To balance the equation, we need an equal number of atoms of each element on both sides. Let's balance it:
2NBr3 + 6NaOH ---> N2 + 3NaBr + 3H2O
Looking at bromine (Br), there are two bromine atoms on the left side and three bromine atoms on the right side. Therefore, we need to multiply NaBr by 2:
2NBr3 + 6NaOH ---> N2 + 6NaBr + 3H2O
Next, let's balance sodium (Na). We have 6 sodium atoms on the right side, so we need to multiply NaOH by 6:
2NBr3 + 6NaOH ---> N2 + 6NaBr + 3H2O
Lastly, let's check nitrogen (N) and oxygen (O). Both are already balanced.
So, the balanced chemical equation is:
2NBr3 + 6NaOH ---> N2 + 6NaBr + 3H2O
In this reaction, nitrogen tribromide (NBr3) reacts with sodium hydroxide (NaOH) to produce nitrogen gas (N2), sodium bromide (NaBr), and water (H2O).