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March 4, 2015

March 4, 2015

Posted by **Nick** on Thursday, April 10, 2014 at 11:31am.

- Math -
**Steve**, Thursday, April 10, 2014 at 11:39amI assume you want values of x which solve the equation.

Well, you know the rational roots will be of the form 1,2,5,10 or 1/5,2/5

A little synthetic division shows that x+1 divides twice, so you have

(x+1)(x+1)(5x^2-51x+10)

Now you can easily see that it is

(x+1)(x+1)(x-10)(5x-1) = 0

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