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March 29, 2015

March 29, 2015

Posted by **Mat** on Thursday, April 10, 2014 at 9:09am.

(i) 1.5e^jπ/4

(ii) je^1.2 + j^2 e

- Math -
**Steve**, Thursday, April 10, 2014 at 11:54ame^jπ/4 = cos(π/4) + j sin(π/4) = 1/√2 + 1/√2 j

Assuming j^2 = -1, you have

-e + e^1.2 j

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