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March 30, 2015

March 30, 2015

Posted by **Vanessa** on Wednesday, April 9, 2014 at 10:48pm.

(e^(4 x) + e^(-5 x)) dx

- Math -
**Steve**, Thursday, April 10, 2014 at 12:15amrecall that ∫ e^u du = e^u

∫e^(4x) dx

let u = 4x, so du = 4 dx. That means that you have

∫e^(4x) (1/4)(4x dx) = ∫ 1/4 e^u du = 1/4 e^u = 1/4 (e^4x)

similarly, for any constant a,

∫e^(ax) dx = 1/a e^(ax)

and as always, don't forget the +C !

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