Posted by **dddd47906 ** on Wednesday, April 9, 2014 at 5:33pm.

Okay now. New question. Find the number of (m) ways in which 6 people can ride a toboggan if ONE OUT OF THREE people must drive.

M=?

PLEASE DO NOT SOLVE! Just tell me how to do the problem. You MIGHT use factorial.

- Math -
**Steve**, Wednesday, April 9, 2014 at 5:42pm
If you mean that the 6-person team must contain 3 drivers, then

the driver can be selected in 3 different ways

The remaining 5 riders can be arranged in P(5) = 5! ways

If I have misread the problem, please clarify.

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**dddd47906 **, Wednesday, April 9, 2014 at 5:44pm
I think you kind of misread it.

I meant that there was ONE driver, although you pick 1 driver out of THREE drivers. Thank you for your time though.

- Math -
**dddd47906 **, Wednesday, April 9, 2014 at 5:51pm
Can anyone answer my question?

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**Steve**, Wednesday, April 9, 2014 at 5:53pm
If you read carefully, I think you will find I did. 3 ways to choose the driver,

5! ways to arrange the riders.

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**dddd47906 **, Wednesday, April 9, 2014 at 6:07pm
thank you for your help!

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**dimpho**, Monday, August 17, 2015 at 5:15pm
there are six people and on the selected 3, 1 must be a driver. so out of the three selected, there are three wasmys to select 1 driver. we minus 1 from the six people then we be left by 5...5!.

the answer is: 3×5!= 360 ways

- Math -
**dimpho**, Monday, August 17, 2015 at 5:16pm
there are six people and on the selected 3, 1 must be a driver. so out of the three selected, there are three ways to select 1 driver. we minus 1 from the six people then we be left by 5...5!.

the answer is: 3×5!= 360 ways

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