Posted by **Anonymous** on Wednesday, April 9, 2014 at 4:56pm.

A women student is to answer 10 out of 13 questions on a test. Find the number of choices where she must answer:

(a) the first two questions;

(b) the first or second questions but not both;

(c) exactly 3 out of the first 5 questions

(d) at least 3 of the first 5 questions

EXCEPTIONS!!!!!!!!!!:

PLEASE DO NOT SOLVE THE PROBLEM!!!

- Math(Factorial) -
**bobpursley**, Wednesday, April 9, 2014 at 5:01pm
how many possible answers are there to each question?

- Math(Factorial) -
**dddd47906**, Wednesday, April 9, 2014 at 5:09pm
you must find out how many ways and also following the rules a,b,c, and d.

P.S. dddd47906 is me! i just signed up...

- Math(Factorial) -
**bobpursley**, Wednesday, April 9, 2014 at 5:11pm
do you mean <answer correctly>?

If each question has 5 answers, there are five ways to answer each question. How many possible answers are there to each question?

- Math(Factorial) -
**dddd47906**, Wednesday, April 9, 2014 at 5:16pm
She must answer a, b, c, and d. You have to answer how many choices she has to answer 10 out of 13 questions while she must answer a, b, c, and d.

- Math(Factorial) -
**bobpursley**, Wednesday, April 9, 2014 at 5:20pm
Perhaps we are using a,b,c,d too many times. You have a,b,c,d listed in the questions as part of the question itself. Is there also 4 possible answers to each question?

- Math(Factorial) -
**dddd47906**, Wednesday, April 9, 2014 at 5:26pm
just to say then- How many ways can she do 10(I MEAN 10!) out of 13 questions also doing (a), (b), (c), and (d)?

- Math(Factorial) -
**bobpursley**, Wednesday, April 9, 2014 at 5:43pm
the number of distinct anagrams of the word MISSISSIPPI is:

11!}{1!4!4!2!}.

a. so answering the first two, you have 11 left, of which 8 are answered, 3 are not.

number ways: 11!/(8!3!)

b. first or second, but not both

first answered, third not: You have 9 to answer, out of 11 choices 11!/9!2!

third answered, first not: same as above.

total ways: add the two.

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