The picture below shows a container that Rene uses to freeze water.

A cylinder is shown with base diameter of 6 centimeters and the height as 8 centimeters.

What is the minimum number of identical containers that Rene would need to make 2000 cm3 of ice? (Use π = 3.14.)

27

9

14

20

volume per cylinder: pi*9*8 = 226.19

2000/226.19 = 8.84

14

IncorrectQuestion 6

0 / 1 pts
(08.02 MC)

The picture below shows a container that Rene uses to freeze water:

A cylinder is shown with base diameter of 6 centimeters and the height as 8 centimeters.

What is the minimum number of identical containers that Rene would need to make 2,000 cm3 of ice? (Use π = 3.14.) (1 point)

14
20
9
27

the answer isn't 14

It's nine...

I'm just gonna take your word for it BlueStar

To find the minimum number of identical containers that Rene would need to make 2000 cm3 of ice, we first need to calculate the volume of a single container.

The formula for the volume of a cylinder is given by V = πr^2h, where V is the volume, r is the radius of the base, and h is the height.

Given that the base diameter is 6 centimeters, we can calculate the radius as half of the diameter, which is 6/2 = 3 centimeters.

Now, substituting the values into the volume formula, we have V = 3.14 * (3^2) * 8, which simplifies to V = 3.14 * 9 * 8, and further simplifies to V = 226.08 cm3.

Therefore, a single container has a volume of 226.08 cm3.

To find the minimum number of containers needed to make 2000 cm3 of ice, we divide the desired volume by the volume of an individual container: 2000 cm3 / 226.08 cm3 ≈ 8.85.

Since we cannot have a fraction of a container, we round up to the nearest whole number.

Therefore, the minimum number of identical containers that Rene would need is 9.

So, the correct answer to the question is 9.