how many Btu of heat are required to melt 8.35 lb of ice at 32 degrees F
To determine the amount of heat required to melt ice, you can use the following equation:
Q = m * ΔH_f
where:
Q is the heat energy (in BTU)
m is the mass of the substance (in pounds)
ΔH_f is the heat of fusion for the substance (in BTU/pound)
In this case, we are melting ice, which has a heat of fusion of 144 BTU/pound.
So, to find the heat required to melt 8.35 lb of ice, we can use the equation as follows:
Q = 8.35 lb * 144 BTU/pound
Calculating this, we get:
Q = 1202.4 BTU
Therefore, 1202.4 BTU of heat energy is required to melt 8.35 lb of ice at 32 degrees Fahrenheit.