To what volume should you dilute 60mL of a 12.0M H2SO4 solution to obtain a 1.85M H2SO4 solution?
The dilution formula is
c1v1 = c2v2
c = concn
v = volume
12.0M x 60mL = 1.85M x ?mL
Solve for ? mL
Actually, I think it is easier to
remember mL x M = mL x M
To determine the volume to which you should dilute a solution, you can use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
For this specific question, you have:
C1 = 12.0 M
V1 = 60 mL
C2 = 1.85 M (final desired concentration)
V2 = volume to be determined
Using the formula, you can rearrange it to solve for V2:
V2 = (C1 * V1) / C2
Substitute the given values into the formula:
V2 = (12.0 M * 60 mL) / 1.85 M
V2 ≈ 390.2 mL
So, to obtain a 1.85 M H2SO4 solution from a 12.0 M H2SO4 solution, you would need to dilute the 60 mL of the 12.0 M H2SO4 solution to a volume of approximately 390.2 mL.