4m^2-24m+36=0

Ok, trent, so if solving for m use this formula: (Google quadratic formula to see formula) so, -b should be 24, b^2 should be -24^2, a should be 4 and c should be 36. The answer should be m=3. -------But if you are to foil this, then 4m^2-24m+36 will be (4m-12)(m-3).

I would divide by 4 to get

m^2 - 6m + 9 = 0 , and now see it as a perfect square
(m-3)^2 = 0
m-3 = 0
m = 3

To solve the quadratic equation 4m^2 - 24m + 36 = 0, we can use the quadratic formula.

The quadratic formula states that for any quadratic equation in the form of ax^2 + bx + c = 0, the solutions for x can be found using the formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In the given equation, we have a = 4, b = -24, and c = 36.

Substituting these values into the quadratic formula, we get:

m = (-(-24) ± √((-24)^2 - 4(4)(36))) / (2(4))
m = (24 ± √(576 - 576)) / 8
m = (24 ± √0) / 8

The discriminant (b^2 - 4ac) is 0 in this case, which means that the equation has exactly one real root. When the discriminant is 0, the ± part of the quadratic formula simplifies to just ±0, resulting in one solution.

Therefore, m = 24 / 8
m = 3

So, the only solution to the quadratic equation 4m^2 - 24m + 36 = 0 is m = 3.