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March 1, 2015

March 1, 2015

Posted by **luna** on Monday, April 7, 2014 at 1:57pm.

- Math (check) -
**Reiny**, Monday, April 7, 2014 at 2:26pmInterpretation #1 : Slant height is the edge of the pyramid

Consider the right-angled (internal) triangle formed by the height , half the diagonal of the base and hypotenuse being the slant height.

let the slant height be x

let the diagonal of the base be d

d^2 = 1^2 + 12^2 = 288

d^2 = 288

d = 12√2

d/2 = 6√2

then x^2 = (d/2)^2 + 8^2 = 72 + 64 = 136

x+ √136 = 2√34 or appr 11.66

Interpretation #2 : slant height is the altitude of one of the triangles:

Consider one of the triangles whose base runs from the centre of the pyramid to the midpoint of a base side, with height 8 and hypotenuse as your "slant height"

base = 6

slant height = hypotenuse = y

height =8

where y^2 = 8^2 + 6^2 = 100

y = √100 = 10

Check: notice I can obtain the edge length from this as well

x^2 = y^2 + 6^2

x^2 = 100+36 = 136

x = √136 (same as above)

- Math (check) -
**luna**, Monday, April 7, 2014 at 3:29pmthank you!

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