Posted by **luna** on Monday, April 7, 2014 at 1:57pm.

what is the slant height for the given pyramid to the nearest whole unit? with a pyramid base of 12cm and a height of 8cm. MY ANSWER: 14

- Math (check) -
**Reiny**, Monday, April 7, 2014 at 2:26pm
Interpretation #1 : Slant height is the edge of the pyramid

Consider the right-angled (internal) triangle formed by the height , half the diagonal of the base and hypotenuse being the slant height.

let the slant height be x

let the diagonal of the base be d

d^2 = 1^2 + 12^2 = 288

d^2 = 288

d = 12√2

d/2 = 6√2

then x^2 = (d/2)^2 + 8^2 = 72 + 64 = 136

x+ √136 = 2√34 or appr 11.66

Interpretation #2 : slant height is the altitude of one of the triangles:

Consider one of the triangles whose base runs from the centre of the pyramid to the midpoint of a base side, with height 8 and hypotenuse as your "slant height"

base = 6

slant height = hypotenuse = y

height =8

where y^2 = 8^2 + 6^2 = 100

y = √100 = 10

Check: notice I can obtain the edge length from this as well

x^2 = y^2 + 6^2

x^2 = 100+36 = 136

x = √136 (same as above)

- Math (check) -
**luna**, Monday, April 7, 2014 at 3:29pm
thank you!

## Answer This Question

## Related Questions

- Math ASAP - 1. What is the length of the diagonal for the rectangular prism with...
- Mathematics - OPQRS is a right pyramid whose base is a square of sides 12cm each...
- Maths - OPQRS is a right pyramid whose base is a square of sides 12cm each. ...
- Maths - OPQRS is a right pyramid whose base is a square of sides 12cm each. ...
- Math - 1.what is the slant height for the given pyramid to the nearest whole ...
- Please Check My Math Answers. Thanks! - Can someone please be kind enough to ...
- math - check my answers pls 1. which solid has two bases that are triangles and ...
- geometry - check my answers pls 1. which solid has two bases that are triangles ...
- Math - Calculate the slant height for the given square pyramid. Round to the ...
- Maths - Solve the equation:a right pyramid with vertical height stand on ...

More Related Questions