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Posted by on Monday, April 7, 2014 at 12:56pm.

Two towers P and Q are 600m apart with P being due east of Q. A church is on a bearing of 210 degrees from P and 125 degrees from Q. Find the distance of the church from P and Q.

  • Math - , Monday, April 7, 2014 at 2:02pm

    I labelled the position of the church as C.
    angle C = 85°

    by the sine law:
    CP/sin35 = 600/sin85
    CP = 600sin35°/sin85° = appr 345.5 m

    you do CQ

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