Post a New Question


posted by .

Two ice skaters start out motionless in the center of an ice rink. They then push each other apart. The
first skater (mass = 80 kg) moves to the right with a velocity of 2.5 m/s. The second skater (mass = 58 kg)
moves to the left at some unknown speed. If we assume that the ice is frictionless, then this is a case where
the total momentum would be conserved. Given that assumption, what is the velocity of the second skater?

  • Biomechanics -

    P=(m +m)v
    =(80kg +58kg)(2.5)
    =345 kg. M/s

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question