You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)

Probability= ?

My answer is 0.301
3 decimal places. Is this correct?

Yes it is

I also agree

To calculate the probability of all three flights arriving on time, we need to find the product of the individual probabilities for each leg of the trip being on time.

If each specific leg of the trip has a 67% chance of being on time, the probability of a specific leg being on time can be expressed as 0.67.

To find the probability of all three flights being on time, we multiply the probabilities of each leg being on time:

0.67 * 0.67 * 0.67 = 0.300763

Rounded to three decimal places, the probability is approximately 0.301.

Therefore, your answer of 0.301 is correct.