A particular person’s lower leg is 59 cm long and has a mass of 8.0 kg. If allowed to swing freely, with what time period would the leg swing? (Treat the leg as a simple pendulum with length equal to half the leg length and all the leg’s mass concentrated at this point.)

Period=2PIsqrt(l/g)

46.35

To find the time period of the leg swing, we can use the formula for the time period of a simple pendulum:

T = 2π√(L/g)

Where:
T = Time period
π = 3.14159 (approximately)
L = Length of the pendulum
g = Acceleration due to gravity (approximately 9.8 m/s²)

In this case, we are considering the leg as a simple pendulum. The length of the pendulum would be equal to half the leg length, which is 59 cm or 0.59 m. So, we have:

L = 0.5 * leg length = 0.5 * 0.59 m = 0.295 m

Now, we can substitute the values into the formula to calculate the time period:

T = 2π√(0.295/9.8)

T = 2 * 3.14159 * √(0.295/9.8)

Calculating this expression will give us the answer for the time period of the leg swing.