Tuesday

September 30, 2014

September 30, 2014

Posted by **tttt** on Wednesday, April 2, 2014 at 8:36pm.

What should the dimension of the rectangle be in order to minimize the total cost of the fence?

- calculus -
**Reiny**, Wednesday, April 2, 2014 at 8:49pmlet the two equal width be x

let the single side by y

xy = 600

y = 600/x

cost = 20y + 30x

= 20(600/x) + 30x

d(cost)/dx = -12000/x^2 + 30

= 0 for a min of cost

30 = 12000/x^2

x^2 = 400

x = 20

the two equal sides are 20 yds each, and the long side is 600/20 = 30 yds.

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