Posted by Jamie on .
I'm stuck on this problem and only have 2 attempts left.
The Ksp of Zn(OH)2 is 1.8x10^-14.
Find Ecell for the following half-reaction.
Zn(OH)2(s) + 2e^- <-> Zn(s) +2OH^-(aq)
So far I've tried using the following methods, none of which have worked...
Ecell = (0.0592/n)logK
Ecell = E^o - (0.0592/n)logK and found Eo by finding the other half reaction (oxidation of water)and adding the two Eo values.
Ecell = Eo - (0.0592/n)logQ and used stoich to find the concentration of Zn2+ from the Ksp value. Then I plugged it in to Q.