2NaOH + CuSO4 = Na2SO4 + Cu(OH)2

100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M NaOH and 0.5M CuSO4 must be used in mL?

Any help would be awesome- even a formula on how to solve

Two stoichiometry problems; one for Cu(OH)2 to CuSO4 and one for Cu(OH)2 to NaOH. Stoichiometry problems, for the most part, are worked the same way.

Step 1. Convert what you have (100 g Cu(OH)2 to mols. mols = grams/molar mass = ?

Step 2. Convert mols Cu(OH)2 to mols NaOH. You can tell from the coefficients in the balanced equation, that mols NaOH = twice the mols Cu(OH)2.

Step 3. Convert mols NaOH to grams. g = mols x molar mass. Assuming 100% yield that is g NaOH needed to produce 100 g of the product you want.

Do the same thing for converting 100 g Cu(OH)2 to g CuSO4.

To determine the amount of 1M NaOH and 0.5M CuSO4 required, we will use the equation and the stoichiometry of the reaction.

The balanced equation is:
2NaOH + CuSO4 -> Na2SO4 + Cu(OH)2

First, let's calculate the molar mass of Cu(OH)2:
Cu(OH)2 = 63.55 g/mol (Cu) + 2(1.01 g/mol) (H) + 2(16.00 g/mol) (O)
Cu(OH)2 = 97.55 g/mol

Now, we can calculate the amount of Cu(OH)2 required:
100 g Cu(OH)2 x (1 mol / 97.55 g) = 1.025 mol Cu(OH)2

According to the stoichiometry of the reaction, 2 moles of NaOH react with 1 mole of CuSO4 to produce 1 mole of Cu(OH)2. Therefore, we need 2 moles of NaOH for every 1 mole of Cu(OH)2.

Hence, the amount of NaOH required is:
1.025 mol Cu(OH)2 x (2 mol NaOH / 1 mol Cu(OH)2) = 2.05 mol NaOH

Now that we have the amount of NaOH in moles, we can calculate the volume of 1M NaOH solution needed using the formula:

Volume (in L) = (Amount in moles) / (Concentration in mol/L)

Volume (in L) = 2.05 mol / 1 mol/L = 2.05 L

To convert this to milliliters (mL), multiply by 1000:

Volume (in mL) = 2.05 L x 1000 mL/L = 2050 mL

Therefore, you will need to use 2050 mL of 1M NaOH solution.

Similarly, using the same formula, we will calculate the volume of 0.5M CuSO4 solution needed:

Volume (in L) = (Amount in moles) / (Concentration in mol/L)
Volume (in L) = 1.025 mol / 0.5 mol/L = 2.05 L

Converting to milliliters:
Volume (in mL) = 2.05 L x 1000 mL/L = 2050 mL

So, you will need to use 2050 mL of 0.5M CuSO4 solution.

To determine how much of 1M NaOH and 0.5M CuSO4 must be used to obtain 100g of Cu(OH)2 with 100% yield, we need to use stoichiometry and the concept of molarity.

First, let's understand the balanced chemical equation:

2NaOH + CuSO4 -> Na2SO4 + Cu(OH)2

The coefficient of Cu(OH)2 is 1, which means that 1 mole of Cu(OH)2 is produced for every 1 mole of CuSO4 used.

Step 1: Calculate the number of moles of Cu(OH)2 required.

Given the desired mass of Cu(OH)2 is 100g, we can convert it into moles using the molar mass of Cu(OH)2. The molar mass of Cu(OH)2 is the sum of the atomic masses of copper (Cu) and hydroxide (OH) groups:

Cu: 63.55 g/mol
O: 16.00 g/mol (15.999 g/mol rounded to 2 decimal places)
H: 1.01 g/mol (1.008 g/mol rounded to 2 decimal places)

Molar mass of Cu(OH)2 = (63.55 g/mol) + (2 * 1.01 g/mol) + (2 * 16.00 g/mol)

Using a calculator, the molar mass of Cu(OH)2 is found to be approximately 97.55 g/mol.

To calculate the number of moles, divide the mass of Cu(OH)2 by its molar mass:

Number of moles = mass / molar mass
Number of moles = 100 g / 97.55 g/mol

Step 2: Calculate the volume of 1M NaOH required.

Since the reaction equation shows a 1:2 stoichiometric ratio between NaOH and CuSO4, that means we need twice as many moles of NaOH as Cu(OH)2.

Number of moles of NaOH = 2 * number of moles of Cu(OH)2

Given that the NaOH concentration is 1M, it means that there is 1 mole of NaOH per liter of solution (1000 mL).

To calculate the volume of 1M NaOH required, divide the number of moles of NaOH by its concentration:

Volume of 1M NaOH (in liters) = (2 * number of moles of Cu(OH)2) / 1

Since we want the volume in milliliters:

Volume of 1M NaOH (in mL) = (2 * number of moles of Cu(OH)2) * (1000 mL / 1 L)

Step 3: Calculate the volume of 0.5M CuSO4 required.

The stoichiometric relationship between CuSO4 and Cu(OH)2 is 1:1, which means that the number of moles of CuSO4 required is equal to the number of moles of Cu(OH)2.

Given that the CuSO4 concentration is 0.5M, it means that there is 0.5 mole of CuSO4 per liter of solution (1000 mL).

To calculate the volume of 0.5M CuSO4 required, multiply the number of moles of CuSO4 by its concentration:

Volume of 0.5M CuSO4 (in liters) = number of moles of Cu(OH)2 / 0.5

Since we want the volume in milliliters:

Volume of 0.5M CuSO4 (in mL) = number of moles of Cu(OH)2 * (1000 mL / 1 L)

After calculating the volumes of 1M NaOH and 0.5M CuSO4, you will have your answer.