Monday

March 30, 2015

March 30, 2015

Posted by **Alex** on Monday, March 31, 2014 at 5:25pm.

a hemispherical bowl with radius 25cm contains water whose depth is 10cm. what is the water's surface area

- Geometry -
**Damon**, Monday, March 31, 2014 at 5:35pmequation of circle radius 25 :

x^2 + y^2 = 25^2 = 625

now what is x when 15 cm from center (which is ten cm from surface)?

x^2 + 225 = 625

x^2 = 400

x = 20

that is our radius at urface

area = pi (20)^2 = 400 pi = 1257 cm^2

- Geometry -
**Anonymous**, Monday, March 31, 2014 at 5:57pmI could also use the formula of a sphere

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