Posted by **Anonymous** on Monday, March 31, 2014 at 11:41am.

The circle defined by the equation x^2 + y^2 = 18 has two points where the slope of its tangent line is m=1. Find those points.

- Calculus -
**Damon**, Monday, March 31, 2014 at 11:46am
LOL, sketch a graph !

- Calculus -
**Steve**, Monday, March 31, 2014 at 1:02pm
Good idea. However, in an attempt to use your math, and also to apply to a possibly more general problem later, try implicit differentiation:

x^2 + y^2 = 18

2x + 2yy' = 0

y' = -x/y

So, if -x/y = 1 and x^2+y^2 = 18,

2x^2 = 18

x = ±3

Now, figuring y should not be too hard.

## Answer this Question

## Related Questions

- Calculus - There are two neighboring points P and Q on the curve f(x)=x^2 (a) ...
- Calculus (pleas help!) - Find the slope of the tangent line to the ellipse x^2/...
- math - Find two point on a circle x^2+y^2=1 where the slope of the tangent line ...
- Calculus - 55. Find an equation of the tangent line to the graph of f(x) =x^3 - ...
- Calculus - 1) An equation of the line contains points (7/9, 7) and (-7/9) is 2) ...
- Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...
- College Calculus - Let f(x) = 3x^2 - 2x + 1 a) write an equation of the line ...
- Calculus - I have a two part question that pertains to a curve (r(x)) and its ...
- Calculus - Tangent Line - Hi, im having problems with the following problem. The...
- secant line, tangent line - f(x) = sqrt(x-1), 1<=x<=3 Let A = (a,f(a)), ...