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January 25, 2015

January 25, 2015

Posted by **Anonymous** on Monday, March 31, 2014 at 11:41am.

- Calculus -
**Damon**, Monday, March 31, 2014 at 11:46amLOL, sketch a graph !

- Calculus -
**Steve**, Monday, March 31, 2014 at 1:02pmGood idea. However, in an attempt to use your math, and also to apply to a possibly more general problem later, try implicit differentiation:

x^2 + y^2 = 18

2x + 2yy' = 0

y' = -x/y

So, if -x/y = 1 and x^2+y^2 = 18,

2x^2 = 18

x = ±3

Now, figuring y should not be too hard.

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