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Posted by on Monday, March 31, 2014 at 11:12am.

A steel ball hangs in a 147cm thread which is dragged right and then let go. Velocityh of the ball is 2,44m/s when it goes through the middle position.

I don't have any mass given up.

How many degrees to the side had the ball been dragged?

  • Physics - , Monday, March 31, 2014 at 11:39am

    ke of ball at bottom = (1/2) m (2.44)^2
    = 2.98 m

    Pe at top = m g h = m (9.81)(h)
    so
    9.81 h m = 2.98 m
    h = .303 meters

    h = 1.47 (1 - cos theta)
    .303/1.47 = 1 - cos T
    .206 = 1 - cos T
    -cos T = -.794
    T = 37.4 degrees

  • Physics - , Monday, March 31, 2014 at 11:58am

    thank you very much ! i got it half the way but couldn't figure out how to finish it .

  • Physics - , Monday, March 31, 2014 at 12:17pm

    You are welcome :)

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