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February 1, 2015

February 1, 2015

Posted by **Anonymous** on Monday, March 31, 2014 at 3:32am.

- Calculus: Integral -
**Steve**, Monday, March 31, 2014 at 5:32amrecall that sec^2 = 1+tan^2, so you have

∫sec^4(4x) dx

= ∫sec^2(4x)(1 + tan^2(4x)) dx

= ∫sec^2(4x) dx + ∫tan^2(4x) sec^2(4x) dx

= 1/4 tan(4x) + (1/4)(1/3) tan^3(4x)

and you can massage that in several ways.

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