Calculus Help Please!!!
posted by Kim on .
Compute Δy and dy for the given values of x and dx = Δx. (Round your answers to three decimal places.)
y = 3x − x^2, x = 3, Δx = −0.6
Δy=???

at x = 3
y = 3*3  9 = 0
at x = 2.4
y = 3(2.4)  2.4^2 = 1.44
delta y = 1.44 0 = 1.44
dy/dx = 3  2 x
at x = 3
dy/dx = 3  6 = 3
if dx = .6
dy = 3 (.6) = 1.8