A 1230 -kg car is pushing an out-of-gear 2180 -kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push horizontally against the ground with a force of 4420N . The rolling friction of the car can be neglected, but the heavier truck has a rolling friction of 750N , including the "friction" of turning the truck's drivetrain. What is the magnitude of the force the car applies to the truck?

The force from the car on the truck = 4420 - 1230 a

So our task is to find a
total m = 1230 + 2180 = 3410 kg

total F = 4420 - 750 = 3670 N
so
a = 3670/3410 = 1.08 m/s^2
so finally
F on truck = 4420 - 1230 (1.08)
F on truck = 3096 Newtons

Well, well, well, looks like we have a case of a car playing tug-of-war with a truck. Let's see if we can lend a helping hand, or should I say, a witty answer.

To find the force that the car applies to the truck, we need to consider a few factors. First, we'll have to calculate the net force acting on the car and truck system.

The net force on the car is given by the equation:

Net force = Force applied by the car - Rolling friction of the truck

Since the rolling friction of the car is neglected, we can simplify this to:

Net force on the car = Force applied by the car

Now, since the car is pushing the truck, the force applied by the car is also the force applied to the truck.

So, the magnitude of the force that the car applies to the truck is 4420N.

Hope that clears things up!

To find the magnitude of the force the car applies to the truck, we need to consider the forces acting on both the car and the truck.

Let's denote the force exerted by the car as Fc and the force exerted by the truck as Ft. The weight of the car is given by mgc, where m is the mass of the car (1230 kg) and g is the acceleration due to gravity (9.8 m/s^2). Similarly, the weight of the truck is mgt, where m is the mass of the truck (2180 kg) and g is the acceleration due to gravity (9.8 m/s^2).

The net force on the car can be calculated by subtracting the rolling friction (neglected) from the force exerted by the car, so we have:

Net force on the car = Fc - Rolling friction of the car

Since the rolling friction of the car is neglected, the net force is simply equal to the force exerted by the car:

Net force on the car = Fc

The net force on the truck can be calculated similarly, by subtracting the rolling friction from the force exerted by the truck, so we have:

Net force on the truck = Ft - Rolling friction of the truck

Given that the rolling friction of the truck is 750 N, we can write:

Net force on the truck = Ft - 750

Since the car and truck are connected and both experience the same acceleration, the net force on the car must be equal to the net force on the truck. Therefore, we can set up an equation:

Fc = Ft - 750

The force exerted by the car is given as 4420 N, so we can substitute this value into the equation:

4420 = Ft - 750

To solve for Ft, we can rearrange the equation:

Ft = 4420 + 750
Ft = 5170 N

Therefore, the magnitude of the force the car applies to the truck is 5170 Newtons.

To find the magnitude of the force the car applies to the truck, we need to consider the forces acting on both the car and the truck.

1. Consider the forces on the car:
- The driving force exerted by the car pushing against the ground, which is given as 4420 N.
- The force of friction opposing the motion between the car's wheels and the ground, which is neglected.

2. Consider the forces on the truck:
- The force of friction opposing the motion between the truck's wheels and the ground, which is given as 750 N.

Now, since the car is pushing the truck, the two forces (4420 N and 750 N) must add together to create the net force between the car and the truck. We can calculate this net force.

3. Calculate the net force:
Net force = (Driving force on the car) - (Force of friction on the truck)
Net force = 4420 N - 750 N
Net force = 3670 N

Therefore, the magnitude of the force the car applies to the truck is 3670 N.