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January 26, 2015

January 26, 2015

Posted by **james** on Saturday, March 29, 2014 at 2:54pm.

- algebra -
**Reiny**, Saturday, March 29, 2014 at 4:43pmJames, I gave you a detailed solution yesterday for the same question on the assumption that your symbol was supposed to be ≥

You later told me that it was to be ≤

So why don't you just switch all the conditions

e.g. all the domain that worked before, now will not

and the domain that did not work, now will

you could also follow my Wolfram link and change the ≥ to ≤ , which will reflect the graph in the x-axis.

I am sure you can do that.

http://www.jiskha.com/display.cgi?id=1396018412

- algebra -
**Steve**, Saturday, March 29, 2014 at 4:48pmI can't make out the inequality sign, but that really makes no difference to the solution

y = (x-4)(x+2)/(x-3)(x+5)

You know there are roots at -2 and 4, and asymptotes at -5 and 3.

So, the graph will cross the x-axis at -2 and 4.

When x < -5, all factors are negative, so y > 0 : --/-- = +

for -5 < x < -2, --/-+ = -

for -2 < x < 3, -+/-+ = +

for 3 < x < 4, -+/++ = -

for x > 4, ++/++ = +

To verify this, check the graph at

http://www.wolframalpha.com/input/?i=%28%28x-4%29%28x%2B2%29%29%2F%28%28x-3%29%28x%2B5%29%29+for+x+%3D+-7..5

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