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Physic Angular momentum and torque

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What is the angular momentum of a 1.0kg uniform cylindrical grinding wheel of radius 19cm when rotating at 1700rpm ?How much torque is required to stop it in 4.6s ?

  • Physic Angular momentum and torque - ,

    r = 0.19 m
    I =.5 m r^2 =.5 (1)(.19)^2 = .0181 kg m^2

    1700 rev/min * 1 min/60 s * 2 pi rad/rev
    = 178 radians/second = omega

    L =I * omega .0181 * 178 = 3.22 kg m^2/s

    final omega = initial omega - alpha t

    alpha (4.6) = -178
    alpha = - 38.7 radians/s^2

    Torque = I alpha = -.0181 (38.7)
    = - 0.7 kg m^2/s^2 = -0.7 Newton meters

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