Upon decomposition, one sample of magnesium fluoride produced 1.65 kg{\rm kg} of magnesium and 2.58 kg{\rm kg} of fluorine. A second sample produced 1.50 kg{\rm kg} of magnesium. How much fluorine (in grams) did the second sample produce?
MgF2 ==> Mg + F2
......1.65kg..2.58 kg
So you must have started with 1.65 + 2.58 = ? kg MgF2.
MgF2 ==> Mg + F2
.......1.50kg..?
I would use ratio/proportion on this.
(1.65/1.50) = (2.58/x)
Solve for x.
3.4 * 10^3
To find out how much fluorine the second sample produced, we need to use the information given about the first sample.
From the information provided, we know that during decomposition, one sample of magnesium fluoride produced 1.65 kg of magnesium and 2.58 kg of fluorine. This means that the ratio of magnesium to fluorine in magnesium fluoride is 1.65 kg of magnesium to 2.58 kg of fluorine.
To find out how much fluorine the second sample produced, we can set up a proportion using this ratio:
1.65 kg magnesium / 2.58 kg fluorine = 1.50 kg magnesium / x kg fluorine
Cross multiplying, we get:
1.65 kg magnesium * x kg fluorine = 1.50 kg magnesium * 2.58 kg fluorine
Simplifying, we have:
x kg fluorine = (1.50 kg magnesium * 2.58 kg fluorine) / 1.65 kg magnesium
Now, simply plug in the values and calculate:
x kg fluorine = (1.50 kg * 2.58 kg) / 1.65 kg
x kg fluorine = 3.87 kg kg / 1.65 kg
x kg fluorine = 2.3484848484848486 kg
To convert kg to grams, we multiply by 1000:
x g fluorine = 2.3484848484848486 kg * 1000 g/kg
x g fluorine = 2348.4848484848486 g
Therefore, the second sample produced 2348.4848484848486 grams of fluorine. Rounded to two decimal places, it is approximately 2348.48 g of fluorine.