calculate the grams of solute neede to prepare 24 grams of a 13.5% by mass scurose (c12h22o11) solution
[(g solute)/(g solution)]*100 = %
g solute = x
g solution = 24
% = 13.5
Substitute and solve for x
To calculate the grams of solute needed to prepare a 13.5% by mass sucrose (C12H22O11) solution, you need to follow these steps:
Step 1: Identify the given information:
- Mass of the solution: 24 grams
- Mass percentage of the solute: 13.5%
Step 2: Convert the given mass percentage to a decimal value:
13.5% = 13.5/100 = 0.135
Step 3: Set up the equation:
Let x be the grams of sucrose needed.
The equation for mass percent is:
(mass of solute / mass of solution) × 100% = mass percent
So, we can write the equation as:
(x grams / 24 grams) × 100% = 0.135
Step 4: Solve for x:
To solve for x, we need to isolate it on one side of the equation.
(x / 24) = 0.135 / 100
x = (0.135 / 100) × 24
x = 0.0324 grams
Therefore, you would need approximately 0.0324 grams of sucrose (C12H22O11) to prepare a 24 grams 13.5% by mass sucrose solution.