Line AB contains points A (-8, -4) and B (1, -5). The slope of line AB is
A. -7
B. -1/7
C. 1/7
D. 7
(-8, -4) and B (1, -5).
slope is (-5+4)/(1+8) = -1/9
You must have had either +8 or -1 for x.
#2) FG has slope (-5-7)/(-4-3) = 12/7
HI has slope (6-0)/(4+5) = 2/3
neither
#3) GH has slope 4
you want slope -1/4, so
y-3 = -1/4 (x-2)
y = -1/4 x + 7/2
(D)
A (-8, -4) and B (1, -5)
SLOPE = (-5 - -4)/ (1 - -8)
= (-5+4)/(1+8)
= -1/9
F(3,7) and G (-4, -5)
SLOPE = (-5 -7)/(-4-3) = 12/7
H(-1, 0) and I (4, 6)
SLOPE = (6-0)/(4 - -1) = 6/5
NOT PARALLEL AND NOT PERPENDICULAR
y=4x-3 AND (2,3)
3 = 4(2) + b
b = -5
SO
Y = 4 X - 5
SORRY, DID NOT READ THAT PERPENDICULAR WORD.
These were kind of confusing.. Steve / Damon, help, again, please?
Looks like you need to review how to find the slope of a line between two points:
change.in.y divided by change.in.x
and the point-slope form of a line.
point (h,k) with slope m is
y-k = m(x-h)
you guyz are NOOOOOO HELP AT ALL!
2.) Line FG contains points F(3,7) and G (-4, -5). Line HI contains points H(-1, 0) and I (4, 6). Lines FG and HI are
A. Parallel
B. Perpendicular
C. Neither
3.) The equation of line GH is y=4x-3. Write an equation of a line perpendicular to line GH in slope-intercept form that contains points (2, 3).
A. y=4x-3
B. y=-4x-5
C. y=1 over 4x-3
D. y=-1 over 4x+7 over 2