CIE and NIE for 2 K3PO4 + 3 Fe(NO3)2 = 6 KNO3 + Fe3(PO4)2
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To determine the CIE (Complete Ionic Equation) and NIE (Net Ionic Equation) for the given chemical reaction:
Step 1: Write the balanced molecular equation:
2 K3PO4 + 3 Fe(NO3)2 = 6 KNO3 + Fe3(PO4)2
Step 2: Split all the soluble ionic species into their individual ions, representing their charges:
2 K+ + 2 PO4^3- + 3 Fe^2+ + 6 NO3^- = 6 K+ + 6 NO3^- + Fe3(PO4)2
Step 3: Identify the spectator ions, which are ions that appear on both sides of the equation without undergoing any change. In this case, the K+ and NO3- ions are spectator ions since they are present on both sides of the equation.
Step 4: Remove the spectator ions from the equation to obtain the NIE:
2 PO4^3- + 3 Fe^2+ = Fe3(PO4)2
So, the Complete Ionic Equation (CIE) is:
2 K+ + 2 PO4^3- + 3 Fe^2+ + 6 NO3^- = 6 K+ + 6 NO3^- + Fe3(PO4)2
And the Net Ionic Equation (NIE) is:
2 PO4^3- + 3 Fe^2+ = Fe3(PO4)2