The three interior angles of a triangle are in a 1:3:6 ratio. Find the measure of the largest angle?

let the angles be

x , 3x and 6x

x + 3x + 6x = 180

take over ....

The next thing that you do is combine like terms.

For x, it is also 1x, it is the same value.

So, once you do that you combine like terms.

1x + 3x + 6x = 10x

Then, you have:

10x = 180

You then divide both sides by 10 to get the variable on the one side by itself.

10 divided by 10 is 1, so that leaves x on the one side.

180 divided by 10 is 18

So, x = 18, and that is your final answer.

For this type of math you then double-check.

18 + 3(18) + 6(18) = 180

18 + 54 + 108 = 180

180 = 180

So yes, 18 is the answer, and it is the largest angle.

Brady, after all that work, you blew the final answer

x+3x+6x = 180
10x=180
x = 10

but I called the angles x, 3x, and 6x
so the angles are 18° , 54° , and 108°

and of course 108° is the largest angle

To find the measure of the largest angle in a triangle when the interior angles are in a 1:3:6 ratio, we need to follow these steps:

Step 1: Set up the equation
Let's assume that the three interior angles of the triangle are x, 3x, and 6x. These angles are in a 1:3:6 ratio.

Step 2: Use the fact that the sum of the interior angles in a triangle is 180 degrees
According to the triangle angle sum property, the sum of the interior angles of a triangle is always 180 degrees. So, we can write the equation as:
x + 3x + 6x = 180

Step 3: Solve the equation
Combine like terms:
10x = 180

Divide both sides of the equation by 10:
x = 18

Step 4: Determine the measure of the largest angle
To find the measure of the largest angle, substitute the value of x back into the equation for the largest angle:
6x = 6 * 18 = 108

Therefore, the measure of the largest angle in the triangle is 108 degrees.