A typical lightning bolt has about 10.0 C of charge. How many excess electrons are in a typical lightning bolt?
10 = x * 1.6*10^-19
10 * 10^19 = 1.6 x
x = 6.25 * 10^19
well, quite a few, but less than a mol (6*10^23)
To determine the number of excess electrons in a typical lightning bolt, we need to know the elementary charge, denoted as "e." The elementary charge represents the charge of a single electron. It is given by e = 1.602 × 10^-19 C.
To find the number of excess electrons in a typical lightning bolt, we can divide the total charge of the lightning bolt by the elementary charge:
Number of excess electrons = Total charge / Elementary charge
In this case, the total charge of the lightning bolt is given as 10.0 C. So, let's calculate the number of excess electrons:
Number of excess electrons = 10.0 C / (1.602 × 10^-19 C)
Dividing the values, we get:
Number of excess electrons ≈ 624,219,953,125,000,000,000
Therefore, a typical lightning bolt contains approximately 6.24 × 10^20 excess electrons.
To determine the number of excess electrons in a typical lightning bolt, we need to know the charge carried by a single electron and the total charge of the lightning bolt.
The elementary charge, denoted as e, is approximately 1.6 x 10^(-19) coulombs (C). This is the charge carried by a single electron or proton.
Given that a typical lightning bolt has a charge of 10.0 C, we can calculate the number of excess electrons using the formula:
Number of excess electrons = Total charge of the lightning bolt / Charge carried by a single electron
Plugging in the values:
Number of excess electrons = 10.0 C / (1.6 x 10^(-19) C)
Simplifying the expression:
Number of excess electrons = 6.25 x 10^(19) electrons
Therefore, a typical lightning bolt carries approximately 6.25 x 10^(19) excess electrons.